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Boy, am I rusty!
Bob the Shrek, the site helped me realize that.
"MamaQueen's answer is very elegant" :->
Thank you, you are a gentleman. But elegance in math/algebra doesn't count when you're wrong, right?
Anyways, I nominate myself as the most ignored Queenzoner. LOL.
Bob the Shrek, the site helped me realize that.
"MamaQueen's answer is very elegant" :->
Thank you, you are a gentleman. But elegance in math/algebra doesn't count when you're wrong, right?
Anyways, I nominate myself as the most ignored Queenzoner. LOL.
MamaQueen - I didn't even know what quadratic maths was until I looked it up!
Assuming my calculations are correct, and they probably aren't...
There are no real solutions to this problem, because the value of the discriminant (b^2 - 4ac) is negative.
There are no real solutions to this problem, because the value of the discriminant (b^2 - 4ac) is negative.
You are making the age-old error of negating the equiditional content of the prefinitive, which in this case is clearly cross-indexed with the semi-decimal value of the Optusic Factor.
It's simple hemistetics really.
It's simple hemistetics really.
Huhsawhodatoothichickabah???
Flashman, what, if anything, does that mean?
QEs are a fairly simple concept, man, it's not like I'm talkin' Greek :)
Flashman, what, if anything, does that mean?
QEs are a fairly simple concept, man, it's not like I'm talkin' Greek :)
They are only simple, young lady, because you are doing them all wrong.
<---Newbie Of The Year folks!
"you are making the age-old error of negating the equiditional content of the prefinitive, which in this case is clearly cross-indexed with the semi-decimal value of the Optustic Factor"
I agree completely with you Flashman, especially the bit about the "Optustic Factor". ;->
Now, if you may, please check my post about the twilight zone cd player and see if you can enlighten me on that one.
I agree completely with you Flashman, especially the bit about the "Optustic Factor". ;->
Now, if you may, please check my post about the twilight zone cd player and see if you can enlighten me on that one.
Geeks -4ac is a positive number because c is negative. Therefore, the solutions are real numbers. I initially thought the solutions were imiaginary numbers, as I initially overlooked that c was negative.
...as the board is slowly desecrated and perverted by MATH. ARGh.
...just when I thought it COULDNT get any worse
...just when I thought it COULDNT get any worse
Oh, of course. You're right. One moment please...
*solves equation*
Got it now.
x = apprx. .29 or -.85.
*solves equation*
Got it now.
x = apprx. .29 or -.85.
Paloma - How dare you speak blasphemy. LOL
Shall I recieve the blaspheme-of-the-year award?